Prove this identity:

$\displaystyle \sum_{k=0}^{n}$$\displaystyle {n}\choose{k}$ = $\displaystyle {2n}\choose{n}$

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- Jan 29th 2008, 05:30 PMtbyou87Identity using Choose numbers
Prove this identity:

$\displaystyle \sum_{k=0}^{n}$$\displaystyle {n}\choose{k}$ = $\displaystyle {2n}\choose{n}$

Thanks - Jan 29th 2008, 06:03 PMmr fantastic