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Math Help - help with math formula

  1. #1
    Newbie
    Joined
    Apr 2006
    Posts
    3

    Angry help with math formula

    Hi,
    I need help with Maths formula.

    See these numbers

    1, 29, 210, 96, etc..

    There are many such numbers

    You can use helper numbers: 10, 563 (563 = total of the above numbers), or any other number you like

    The answers are : 1, 1, 4, 25, etc..

    How would you achieve this answers?

    I have been trying for a solution for the past 1 month but I haven't found a way or no one was able to help me out.

    Can you help me please?

    Regards,
    Uma
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  2. #2
    Grand Panjandrum
    Joined
    Nov 2005
    From
    someplace
    Posts
    14,972
    Thanks
    4
    Quote Originally Posted by reddyumamaheswar
    Hi,
    I need help with Maths formula.

    See these numbers

    1, 29, 210, 96, etc..

    There are many such numbers

    You can use helper numbers: 10, 563 (563 = total of the above numbers), or any other number you like

    The answers are : 1, 1, 4, 25, etc..

    How would you achieve this answers?

    I have been trying for a solution for the past 1 month but I haven't found a way or no one was able to help me out.

    Can you help me please?

    Regards,
    Uma
    I think you will heve to supply more information if you want a constructive
    answer.

    The Online Encyclopedia of Interger Sequences does not recognise it.

    RonL
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  3. #3
    Newbie
    Joined
    Apr 2006
    Posts
    3

    Exclamation

    Hi,
    This is the total numbers for which I need answers

    1, 29, 210, 96, 3, 20, 29, 18, 5, 1, 54, 1, 4, 4, 4, 27, 1, 15, 17, 21, 3

    The total of these numbers = 563

    The above numbers might vary i.e. 1 can be 5 and 29 can be 8. But that is all abstract and we dont know what change might be there and when.

    I am showing 10 numbers at one time. i.e. for the fist time I will show 1 - 10 out of 563 and for the second time I will show 11 - 20 out of 563 and the series goes on till 563 numbes are shown.

    And note that to complete this process, I will loop for 56 times i.e. 563 / 10

    I wanted to create a formula where in I can go directly into a specic number lot i.e. 1 - 56

    So what I am doing here is

    A. 1 / 10 = 0

    B. 1 + 29 = 30 / 10 = 3

    C. 1 + 29 + 210 = 240 / 10 = 24

    You can see the answers 0, 3, 24 which actually corresponds to the ending number lot

    for example scenario "C" the number lot starts from 31 - 240 and so the number lot answer should be 4 since it has crossed 1 - 10 , 11 - 20, 21 - 30, 31 - 40 (STARTED)

    I hope I am clear, Please let me know if there is something more I am missing?

    Thank you,
    Regards,
    Uma
    Last edited by reddyumamaheswar; April 20th 2006 at 08:20 PM.
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  4. #4
    Newbie
    Joined
    Apr 2006
    Posts
    3

    Exclamation

    Is there no one who can help me?
    Follow Math Help Forum on Facebook and Google+

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