This is not transitive, since we have 3R2 and 2R3 but not 3R3

in short, here's what you need to know.

Implications are false only when the first statement is true and the second is false. that is, is false ONLY if P is true and at the same time Q is false.

based on that, we can have something being transitive "vacuously"

e.g. the empty set is vacuously transitive. but you might say, how can that be, there are no elements to relate to the definition. but that is exactly it, that would mean we have no two element to compare for the statement "If aRb and bRc", so the first statement of the implication is false, and so the whole implication "if aRb and bRc then aRc" is true

another thing you need to note is that you can reuse elements. for instance, the relation defined by R = {(1,1)} IS transitive. How? we have 1R1 and 1R1 implies 1R1. which clearly conforms to our definition.

so look at the relations again and check if they conform to the definition