If R is symmetric then the standard proof that so is follows: .
You should be able to extend that
Yeah.. I do get what you mean.
because we have 5 as a power.. 5 is an odd number. So we will be missing a pair making the relation not symmetric..
So the answer should be No.. I guess..??
Anyway, thanks for the help man. Really appreciate it.
Yeah.. I do get what you mean.
because we have 5 as a power.. 5 is an odd number. So we will be missing a pair making the relation not symmetric..
So the answer should be No.. I guess..??
You have been mislead by my posting!
We have shown that is symmetric.
Now suppose that then for some z, .
But we already have shown that .
This is the reason that you may have been lead to think that it is a proof by induction.
In fact, is symmetric.