For all k>0,k∈ℤ . Prove

I think I understand what this wants but i can't figure out how to set up a formal proof. These are the guidelines we have to follow http://i.imgur.com/qpIYqPp.pnggcd(k∗a,k∗b)=k∗gcd(a,b)

Can anyone help me figure this out

Printable View

- April 21st 2014, 08:59 PMshmiksstruggling with proof: gcd(k∗a, k∗b)=k∗gcd(a, b)
For all k>0,k∈ℤ . Prove

I think I understand what this wants but i can't figure out how to set up a formal proof. These are the guidelines we have to follow http://i.imgur.com/qpIYqPp.pnggcd(k∗a,k∗b)=k∗gcd(a,b)

Can anyone help me figure this out - April 21st 2014, 09:14 PMSlipEternalRe: struggling with proof: gcd(k∗a, k∗b)=k∗gcd(a, b)
Any time you are working with gcd, you will probably want to start with terms of the form . You might even want to consider the set . The minimum of that set is the gcd. Next show that the right hand side produces a divisor of both ka and ka. Then show it produces a greatest divisor.