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Math Help - lost again

  1. #1
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    Question lost again

    Give a formula for the coefficient of x^k in the expansion of (x^2 - 1/x)^100, where k is an integer. ( x^8 means x to the power of 8, ^ means to the power of).
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    Quote Originally Posted by lkrb View Post
    Give a formula for the coefficient of x^k in the expansion of (x^2 - 1/x)^100, where k is an integer. ( x^8 means x to the power of 8, ^ means to the power of).
    Use the binomial theorem:
    (a + b)^n = \sum_{k = 0}^n {n \choose k}  a^{n-k}b^k

    So here we have a = x^2 and b = \frac{1}{x}. You do the rest.

    -Dan
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