gender probabilty

• Nov 11th 2007, 10:31 AM
lkrb
gender probabilty
assume that the probability a child is a boy is 0.51 and that the sexes of children born into a family are independent. What is the probability that a family of five children has exactly three boys? At least one boy? All children of the same gender?
• Nov 11th 2007, 11:18 AM
CaptainBlack
Quote:

Originally Posted by lkrb
assume that the probability a child is a boy is 0.51 and that the sexes of children born into a family are independent. What is the probability that a family of five children has exactly three boys? At least one boy? All children of the same gender?

This is another binomial distribution problem, we will take that a child is a
boy as the favourable outcome, so in a family with n children the probability
of k boys is b(k;n,0.51).

So the probability of 3 boys in a family with 5 children is b(3;5,0.51)

The probability of at least one boy = 1-prob(no boys)=1-b(0;5,0.51).

Prob all the children the same gender = (prob all girls) + (prob all boys) = b(0,5,0.51)+b(5;5,0.51).

RonL