I encountered a few questions I really have no idea how to even start approaching... Any help would be much appreaciated!
(id = identity)
prove that if f: A->B is a surjective (onto) function, then there exists a function g: B->A such that f composition g = idB
let f: A->B, g: A->B, h: B->A functions.
prove or disprove:
1. if h composition f = idA then f composition h = idB
2. if h composition f = idA and f is surjective (onto), then f composition h = idB
3. if h composition f = idA and h composition g = idA then g=f.
Thank you (: