What is the big 0 of (2^n+n^2)(n^3+3^n).

I get that I foil this out. If I did this correctly, I get that this is O(6^n). Is this right or did I mess up somewhere?

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- Oct 14th 2013, 09:35 AM #1

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- Oct 14th 2013, 10:17 AM #2

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- Oct 14th 2013, 02:11 PM #3

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- Oct 14th 2013, 02:25 PM #4

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- Oct 16th 2013, 09:25 AM #5

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## Re: Big O problem

The function log(log(n)) grows very, v e r y slowly. If the logs are based 10, it returns 2 for n=10¹⁰⁰, which is greater than the number of particles in the universe. Nevertheless, this function tends to infinity as n → ∞.

I am not sure what exactly you difficulty with log(log(n)) is. Feel free to post concrete questions about these functions.

- Oct 16th 2013, 08:49 PM #6

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