# Thread: Convert boolean expression into SOP and POS algebraically

1. ## Convert boolean expression into SOP and POS algebraically

Question:

Convert the following boolean expression into SOP and POS canonical forms using boolean algebra method.
$(ac + b)(a + \overline{b}c) + ac$

Attempt at solution:

$(ac + b)(a + \overline{b}c) + ac$

1. $(a + b)(c + b)(a + \overline{b})(a + c) + ac$
2. ??
3. ??

That's as far as I got. I'm not sure what I'm supposed to do next. Help appreciated. Thank you.

2. ## Re: Convert boolean expression into SOP and POS algebraically

Hey larry21.

What does SOP and POS mean for readers like myself who are unfamiliar with these terms?

3. ## Re: Convert boolean expression into SOP and POS algebraically

SOP = sum of products
POS = product of sums

4. ## Re: Convert boolean expression into SOP and POS algebraically

Hint: Can you reduce (a + c) + ac to simply (a + c) [Check the truth table for verification]?