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Math Help - Convert boolean expression into SOP and POS algebraically

  1. #1
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    Convert boolean expression into SOP and POS algebraically

    Question:

    Convert the following boolean expression into SOP and POS canonical forms using boolean algebra method.
    (ac + b)(a + \overline{b}c) + ac

    Attempt at solution:


    (ac + b)(a + \overline{b}c) + ac

    1. (a + b)(c + b)(a + \overline{b})(a + c) + ac
    2. ??
    3. ??

    That's as far as I got. I'm not sure what I'm supposed to do next. Help appreciated. Thank you.
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  2. #2
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    Re: Convert boolean expression into SOP and POS algebraically

    Hey larry21.

    What does SOP and POS mean for readers like myself who are unfamiliar with these terms?
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  3. #3
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    Re: Convert boolean expression into SOP and POS algebraically

    SOP = sum of products
    POS = product of sums
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  4. #4
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    Re: Convert boolean expression into SOP and POS algebraically

    Hint: Can you reduce (a + c) + ac to simply (a + c) [Check the truth table for verification]?
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