# Convert boolean expression into SOP and POS algebraically

• Oct 12th 2013, 09:24 AM
larry21
Convert boolean expression into SOP and POS algebraically
Question:

Convert the following boolean expression into SOP and POS canonical forms using boolean algebra method.
$\displaystyle (ac + b)(a + \overline{b}c) + ac$

Attempt at solution:

$\displaystyle (ac + b)(a + \overline{b}c) + ac$

1. $\displaystyle (a + b)(c + b)(a + \overline{b})(a + c) + ac$
2. ??
3. ??

That's as far as I got. I'm not sure what I'm supposed to do next. Help appreciated. Thank you.
• Oct 12th 2013, 06:29 PM
chiro
Re: Convert boolean expression into SOP and POS algebraically
Hey larry21.

What does SOP and POS mean for readers like myself who are unfamiliar with these terms?
• Oct 12th 2013, 09:49 PM
larry21
Re: Convert boolean expression into SOP and POS algebraically
SOP = sum of products
POS = product of sums
• Oct 13th 2013, 04:35 PM
chiro
Re: Convert boolean expression into SOP and POS algebraically
Hint: Can you reduce (a + c) + ac to simply (a + c) [Check the truth table for verification]?