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Math Help - Algebraic Manipulation Part 2.

  1. #1
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    Wink Algebraic Manipulation Part 2.

    Use algebraic manipulation to prove that xy + yz + x!z = xy + x!z (Note that this is the consensus property in section 2.5) [This is the property they are talking about: xy + yz + x!z = xy + x!z]

    So I have:
    xy + yz + x!z = xy + x!z

    I'm lost.. Do they want me to factor? the left hand side first? or am I just making the left hand side look like the right y(x + z) + x!z? thus: yx +yz + x!z = xy + yz + x!z?

    or do they want something like x(y + z) + x!

    Is this correct?

    Sham
    Last edited by shamieh; September 12th 2013 at 09:44 AM.
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  2. #2
    MHF Contributor
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    Re: Algebraic Manipulation Part 2.

    Hey shamieh.

    I took a look at Wikipedia (I cheated on this one), but the key step is to use the fact that x! + x = 1 (where x is any variable).
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  3. #3
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    Re: Algebraic Manipulation Part 2.

    Can anyone solve this? I need a detailed explanation so I can see it happening visually.
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