Algebraic Manipulation Part 2.

Use algebraic manipulation to prove that xy + yz + x!z = xy + x!z (Note that this is the consensus property in section 2.5) [This is the property they are talking about: **xy + yz + x!z = xy + x!z**]

So I have:

**xy + yz + x!z = xy + x!z **

I'm lost.. Do they want me to factor? the left hand side first? or am I just making the left hand side look like the right **y(x + z) + x!z?** thus: **yx +yz + x!z = xy + yz + x!z?**

or do they want something **like x(y + z) + x!**

Is this correct?

Sham

Re: Algebraic Manipulation Part 2.

Hey shamieh.

I took a look at Wikipedia (I cheated on this one), but the key step is to use the fact that x! + x = 1 (where x is any variable).

Re: Algebraic Manipulation Part 2.

Can anyone solve this? I need a detailed explanation so I can see it happening visually.