Help with proving a function is not onto.

Suppose that f:A->B and g:B->C. Prove that if f is not onto and g is one-to-one, then gof is not onto.

Am I right in saying that we need to find some x in B which shows that f is not onto? Then we can say that for any a in A, gof(a) does not equal g(x)? I don't know where to go from here or even if "here" is a starting point.

Thanks for any help!

Also, how do you use LaTeX in this forum? I've seen it used in other posts but I can't figure out how to do it.

1 Attachment(s)

Re: Help with proving a function is not onto.

Hi,

To use Latex, see the forum Latex Help. For this specific function problem, see the attachment:

Attachment 29121