Please help in finding the properities of relation of following pair which is solved from a graph.
Sorry if my question is not clear enough to understand, but actually I myself dont know what the purpose of the Properties of Relation and how we can determine them from the graph ..
as you can read the question from attached file in MS Batool reply..
Set of pair for picture 1 is as :
It's matrix is as :
0 1 1 0 0
0 0 0 0 0
0 0 0 1 1
0 0 0 0 0
0 0 0 0 0
If you please help us in " what did mean of Properties of the relation" then we might solve it.
As to your last demand, there is simply not enough information given to answer the questions. Because you steadfastly refuse to give any more information, I conclude that you simply want the done for without putting out any effort on your part.
Well, NO I will not do that!
Thanks for your kind reply. Though it make me feel that you are bit harsh without knowing that MS BATOOL is just a newbie and we know very well that such words are not considered in good context on web forums..
I apologies on beholf of MS BATOOL.
I really appreciate the efforts of you people to help us without any interest, at the same time I would request you to avoid such hard words to disheart members..
The only reason for hurry from MS BATOOL is because today is the last day of assignment and now we have to upload as it is.
Infact I am not an expert of Math that's why I couldnt explain well my question, but I tried my best to explain it.. even I have solved the most of the pat except "determining the Properties of Relation" which may be is the explanation of whether the function is one-to-one or onto, as MS BATOOL has written. but i'm not sure.
I again say sorry, if our words hurt you.. but these were unintentionaly.
Thanks all of you.
can you explain one to one relationship and onto realtionship?
i will be very thankful to you
The relations are as follows: -
a) (x1, x3),(x1,x2),(x3,x5),(x3,x4)
b) (x1,x4),(x1,x1),(x4,x4),(x4,x1),(x2,x2),(x2,x1),(x 1,x2),(x3,x3),(x3,x2),(x2,x3)
Reflexive and Symmetric
Though it get little late, but it might help someone else in future...
Thanks to all of you.