It isn't possible. What values do you get for and 8! ?
According to Wikipedia, Derangement - Wikipedia, the free encyclopedia, 8!= 40320 while .
How is it possible that D_{8} > 8! ?
8! is the number of all possible permutations of 8 elements, and D_{8} is the number of permutations such that no element is in its position.
So {set of derangements} {set of permutations}.
How can there be more derangements than permutations of the same number of elements?
It isn't possible. What values do you get for and 8! ?
According to Wikipedia, Derangement - Wikipedia, the free encyclopedia, 8!= 40320 while .