prove that for all n>1 , 10^n -1 is divisible by 9. Include both a basis step and an inductive step.
so for the basis step i have
let n =1 10(1) - 1 / 9
9 / 9 = 1
1>1
If you think that $\displaystyle 10^2=20$ then you have absolutely no business even trying this question.
You don't even seem to have any idea what is meant by the inductive step. Do you?
Seek live help. We are not able to give you the sort of attention that you appear to need.