If you divide a 5 digit number by a 2 digit number, how many digits will the remainder have?
It will have 2 digits but is there a practical way to solve that type of questions?
There is a way and its through logarithms.
The number of digits left over after dividing m into n digit will be ln(m/n) = ln(m) - ln(n) where ln(m) is the number of digits (in fractional form) and ln(n) is the number of digits for n (again in fractional form).
You can round the log results but that's the basic idea.