If you divide a 5 digit number by a 2 digit number, how many digits will the remainder have?

It will have 2 digits but is there a practical way to solve that type of questions?

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- Mar 6th 2013, 12:11 AMkastamonudivision
If you divide a 5 digit number by a 2 digit number, how many digits will the remainder have?

It will have 2 digits but is there a practical way to solve that type of questions? - Mar 6th 2013, 12:29 AMchiroRe: division
Hey kastamonu.

There is a way and its through logarithms.

The number of digits left over after dividing m into n digit will be ln(m/n) = ln(m) - ln(n) where ln(m) is the number of digits (in fractional form) and ln(n) is the number of digits for n (again in fractional form).

You can round the log results but that's the basic idea. - Mar 6th 2013, 12:35 AMkastamonuRe: division
for example 59873 by 45,

Logarithm method is not a quick way. You have to look for the log table. I need a more quick way to get the answer in 1-2 minutes. - Mar 8th 2013, 12:25 PMemakarovRe: division
By definition, the remainder does not exceed the divisor, so it will have

*at most*two digits. - Mar 9th 2013, 02:22 AMkastamonuRe: division
Many Thanks.