Math Help - sequences

Find the limit of (1+(4/3n+1))^6n.

I found it as e^6. [(1+(4/3/n+1)/(3))^6]^n and by the equation (1+1/x)^x=e,it is e^6.

as .

Secondly, this is not discrete mathematics, but calculus.

answer is e^8 but I can't get it.

Originally Posted by kastamonu

Find the limit of (1+(4/3n+1))^6n.

Sorry, this won't work either.

as .

And there is a question whether 4/3n means (4/3)n or 4/(3n).

Originally Posted by kastamonu

Find the limit of (1+(4/3n+1))^6n.

I an sure you mean


If then .

Yes Plato. Many Thanks. But is there a way to derive this formula?

Originally Posted by kastamonu

Yes Plato. Many Thanks. But is there a way to derive this formula?

Write it as .

Let so .

Or .

Many Thanks.