Find the limit of (1+(4/3n+1))^6n. I found it as e^6. [(1+(4/3/n+1)/(3))^6]^n and by the equation (1+1/x)^x=e,it is e^6.
Last edited by kastamonu; February 23rd 2013 at 01:21 PM.
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as . Secondly, this is not discrete mathematics, but calculus.
answer is e^8 but I can't get it.
Originally Posted by kastamonu Find the limit of (1+(4/3n+1))^6n. Sorry, this won't work either. as . And there is a question whether 4/3n means (4/3)n or 4/(3n).
Originally Posted by kastamonu Find the limit of (1+(4/3n+1))^6n. I an sure you mean If then .
Yes Plato. Many Thanks. But is there a way to derive this formula?
Originally Posted by kastamonu Yes Plato. Many Thanks. But is there a way to derive this formula? Write it as . Let so . Or .
Last edited by Plato; February 23rd 2013 at 02:49 PM.
Many Thanks.
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