Find the limit of (1+(4/3n+1))^6n.

I found it as e^6. [(1+(4/3/n+1)/(3))^6]^n and by the equation (1+1/x)^x=e,it is e^6.

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- February 23rd 2013, 11:51 AMkastamonusequences
Find the limit of (1+(4/3n+1))^6n.

I found it as e^6. [(1+(4/3/n+1)/(3))^6]^n and by the equation (1+1/x)^x=e,it is e^6. - February 23rd 2013, 12:10 PMemakarovRe: sequences
as .

Secondly, this is not discrete mathematics, but calculus. - February 23rd 2013, 12:22 PMkastamonuRe: sequences
answer is e^8 but I can't get it.

- February 23rd 2013, 12:27 PMemakarovRe: sequences
- February 23rd 2013, 01:20 PMPlatoRe: sequences
- February 23rd 2013, 01:23 PMkastamonuRe: sequences
Yes Plato. Many Thanks. But is there a way to derive this formula?

- February 23rd 2013, 01:47 PMPlatoRe: sequences
- February 23rd 2013, 01:58 PMkastamonuRe: sequences
Many Thanks.