hello i am working on this study guide for exam 1

determine all the elements in each of the following sets.

{n|0=(n-2)(3n+1)(n-4), n $\displaystyle E$ N}

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- Feb 21st 2013, 05:12 PMzhengcl86Set builder notations, exam #1 next thursday!
hello i am working on this study guide for exam 1

determine all the elements in each of the following sets.

{n|0=(n-2)(3n+1)(n-4), n $\displaystyle E$ N} - Feb 21st 2013, 05:39 PMjakncokeRe: Set builder notations, exam #1 next thursday!
So all natural number solutions to $\displaystyle (n-2)(3n+1)(n-4) = 0$ or n = 2 and n = 4, for $\displaystyle 3n+1 = 0 $ means n = $\displaystyle \frac{-1}{3} $ which is not a natural number.

so you have $\displaystyle \{2,4\} $