4 married couples sit at a round table. How many ways can they sit if each husband must sit opposite his wife?
3!3.2! is my answer.
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4 married couples sit at a round table. How many ways can they sit if each husband must sit opposite his wife?
3!3.2! is my answer.
Quote:
Originally Posted by kastamonu
Seat couple A at the table.
Now there are six ways to seat couple B.
Then there are four ways to seat couple C.
Finally there are two ways to seat couple D.
3!.16 . If we think four couples as one person we can place them in 3! ways. 2 couples will be ordered between themselves and there are 4 couples this makes 16. But your nswer is better. Many Thanks.
Quote:
Originally Posted by kastamonu
I don't know where you are getting your model, but it is wrong.
Draw a regular octagon. There vertices are the eight chairs.
It is not ordered until one couple is seated.
Seat couple A anywhere, but man and wife are at opposite vertices.
Now the table is ordered.
There are six seats left. Seat wife B in any one of them. Then man B has only one place to be seated, at the opposite vertex from wife B.
.
What happens if we want all the couples to sit seperately?
There are 4 married couples. If we think them as 1 person they can be arranged in 3! They will change places between themselves in 2! ways. TRhere are 4 couples and this makes 2!2!2!2!3!
Quote:
Originally Posted by kastamonu
Always, always, start a new thread for a new question.
Using inclusion/exclusion