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Math Help - Urgent pleaseeeeeee

  1. #16
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    Re: Urgent pleaseeeeeee

    Quote Originally Posted by ILikeSerena View Post
    Yes! That is correct.

    So (xy \vee x'y')' = (xy)' \wedge (x'y')' = (x' \vee y') \wedge (x \vee y)

    The logical next step is to try the law of distributivity.
    Care to try?

    I Meant for all 3 parts of this?
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  2. #17
    Super Member ILikeSerena's Avatar
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    Re: Urgent pleaseeeeeee

    I intended the application of the distributive law to ((x' ∨ y')(x)).
    And also to ((x' ∨ y')(y)).
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  3. #18
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    Re: Urgent pleaseeeeeee

    ohhh ok so it would be

    ((x)(x' V y')) = (x V x') ∧ (x V y')

    ((y)(x' V y')) = (y V x')∧ ( y V y')
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  4. #19
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    Re: Urgent pleaseeeeeee

    Good!

    Can you find another law to apply?
    One that resembles the sub expressions you have now?
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  5. #20
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    Re: Urgent pleaseeeeeee



    is it the Absorption 1) x∧(x∨y) = x
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  6. #21
    Super Member ILikeSerena's Avatar
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    Re: Urgent pleaseeeeeee

    I agree that it resembles it, but no, it does not match...

    Another?
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  7. #22
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    Re: Urgent pleaseeeeeee

    is it the of Associativity of ∨) x∨(y∨z) = (x∨y)∨z
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  8. #23
    Super Member ILikeSerena's Avatar
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    Re: Urgent pleaseeeeeee

    Nope. Try complementation.
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  9. #24
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    Re: Urgent pleaseeeeeee

    ohhh so its the x∨x = 1

    and it will be ( y V y') = 1

    but how will I do this one (y V x') ?

    btw thank you soooo much!
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  10. #25
    Super Member ILikeSerena's Avatar
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    Re: Urgent pleaseeeeeee

    Oops. I just noticed I missed a small mistake here.

    Quote Originally Posted by juliie View Post
    ohhh ok so it would be

    ((x)(x' V y')) = (x V x') ∧ (x V y')

    ((y)(x' V y')) = (y V x')∧ ( y V y')

    It should be:
    ((x)(x' V y')) = (x x') V (x y')

    ((y)(x' V y')) = (y x') V ( y y')

    Be careful!



    Now, let's go back to what we have:
    ((xy)∨(x'y'))' = ((x x') V (x y')) ∨ ((y x') V ( y y'))

    You'll need to apply the other law of complementation:
    ((xy)∨(x'y'))' = ((x x') V (x y')) ∨ ((y x') V ( y y')) = (0 V (x y')) ∨ ((y x') V 0)


    Can you do something more with this?
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  11. #26
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    Re: Urgent pleaseeeeeee

    can we do the Identity for ∨) x∨0 = x ?

    so

    (0 V (xy')) = xy'

    (0V(yx')) = yx'
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  12. #27
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    Re: Urgent pleaseeeeeee

    which means (0 V (xy')) V (0V(yx')) = xy' V yx'

    and that's the proof?
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  13. #28
    Super Member ILikeSerena's Avatar
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    Re: Urgent pleaseeeeeee

    Yup!

    Congratulations!
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  14. #29
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    Re: Urgent pleaseeeeeee

    oh my god thank you sooooooooooooooooooo much you're amazing!
    Thanks from ILikeSerena
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