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Math Help - Strange diophantine equation

  1. #1
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    Strange diophantine equation

    k,a,b,c,d be positive integers

    Solve the system of equations

    3^k-2=abcd

    2(3^{k-1}-1)=(a-1)(b-1)(c-1)(d-1)

    or prove that no solutions exist
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  2. #2
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    Re: Strange diophantine equation

    Well, a=b=c=d=k=1 is a solution.
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  3. #3
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    Re: Strange diophantine equation

    Any other solutions beside the trivial one?
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