Re: Need help with induction

Quote:

Originally Posted by

**borab**

$\displaystyle \frac{n(n+1)(2n+1)}{6}+(n+1)^{2}=(n+1)\left[\frac{n(2n+1)+6(n+1)}{6}\right]$

Re: Need help with induction

Hey, thanks for the answer, but I didn't really understand what you did there, can you please explain? Also you still didn't reach

http://latex.codecogs.com/gif.latex?...n+2)(2n+3)}{6}

Re: Need help with induction

Simply put, you just need to factorize one expression in order to get the next one. Plato suggests that you start by putting the (n+1) factor in front. This is given. Then you can work with a simple quadratic expression.

Re: Need help with induction

Quote:

Originally Posted by

**borab**

NO I did not.

That happens to be your job, not mine.

Hint: Multiply $\displaystyle n(2n+1)+6(n+1)$, combine and factor.

Re: Need help with induction

I appreciate the help, but I'm afraid I still don't understand what you're telling me to do, it might be because english isn't my first language. Is there any chance you can show the next step?

Re: Need help with induction

It appears to me that **Plato** has left you the task of showing:

$\displaystyle n(2n+1)+6(n+1)=(n+2)(2n+3)$