Permutation

hello...I need help with this probelm :

How many ways are there for eight men and five women to stand in a line so that no two women stand next to each other? [Hint: First position the men and then consider possible positions for the women.]

This is a problem from rossen's discrete math... the answer is 609,638,400, but i can't get the same answer...

Quote:

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Originally Posted by dedust

How many ways are there for eight men and five women to stand in a line so that no two women stand next to each other? .

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The eight men create nine places to place the five women.

" The eight men create nine places " thank you plato (Bow)