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Math Help - Boolean Algebra Help

  1. #1
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    Boolean Algebra Help

    I need help with simplification.

    x = nA.nB.C + nA.B.nC + nA.B.C + A.nB.nC

    Wasn't sure how to show a NOT so used a small (n) in front of the letter to display that it was notted. If you could give me any tips to solve this or help that would be much appreciated.
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  2. #2
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    Re: Boolean Algebra Help

    Quote Originally Posted by normanthefish View Post
    I need help with simplification.
    x = nA.nB.C + nA.B.nC + nA.B.C + A.nB.nC
    Wasn't sure how to show a NOT so used a small (n) in front of the letter to display that it was notted. If you could give me any tips to solve this or help that would be much appreciated.

    [tex] x = \neg A\cdot \neg B\cdot C + \neg A\cdot B\cdot \neg C + \neg A\cdot B\cdot C + A\cdot \neg B\cdot \neg C [/tex] gives  x = \neg A\cdot \neg B\cdot C + \neg A\cdot B\cdot \neg C + \neg A\cdot B\cdot C + A\cdot \neg B\cdot \neg C
    Click on the “go advanced” tab. On the toolbar you will see \boxed{\Sigma} clicking on that give the LaTeX wraps, [tex] [/tex]. The code goes between them.
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  3. #3
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    Re: Boolean Algebra Help

    The only simplification seems to be factoring out (~A)B from the second and third term (and replacing C + ~C with T).
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  4. #4
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    Re: Boolean Algebra Help

    Still confused with the symbols to use so sticking with what i know.

    managed to get x = nA.nB.C + nA.B + A.nB.nC

    if that is what you meant
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  5. #5
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    Re: Boolean Algebra Help

    Yes, this was my idea.
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