1. Boolean Algebra Help

I need help with simplification.

x = nA.nB.C + nA.B.nC + nA.B.C + A.nB.nC

Wasn't sure how to show a NOT so used a small (n) in front of the letter to display that it was notted. If you could give me any tips to solve this or help that would be much appreciated.

2. Re: Boolean Algebra Help

Originally Posted by normanthefish
I need help with simplification.
x = nA.nB.C + nA.B.nC + nA.B.C + A.nB.nC
Wasn't sure how to show a NOT so used a small (n) in front of the letter to display that it was notted. If you could give me any tips to solve this or help that would be much appreciated.

$$x = \neg A\cdot \neg B\cdot C + \neg A\cdot B\cdot \neg C + \neg A\cdot B\cdot C + A\cdot \neg B\cdot \neg C$$ gives $\displaystyle x = \neg A\cdot \neg B\cdot C + \neg A\cdot B\cdot \neg C + \neg A\cdot B\cdot C + A\cdot \neg B\cdot \neg C$
Click on the “go advanced” tab. On the toolbar you will see $\displaystyle \boxed{\Sigma}$ clicking on that give the LaTeX wraps, . The code goes between them.

3. Re: Boolean Algebra Help

The only simplification seems to be factoring out (~A)B from the second and third term (and replacing C + ~C with T).

4. Re: Boolean Algebra Help

Still confused with the symbols to use so sticking with what i know.

managed to get x = nA.nB.C + nA.B + A.nB.nC

if that is what you meant

5. Re: Boolean Algebra Help

Yes, this was my idea.