# Boolean Algebra Help

• November 22nd 2012, 02:11 PM
normanthefish
Boolean Algebra Help
I need help with simplification.

x = nA.nB.C + nA.B.nC + nA.B.C + A.nB.nC

Wasn't sure how to show a NOT so used a small (n) in front of the letter to display that it was notted. If you could give me any tips to solve this or help that would be much appreciated.
• November 22nd 2012, 02:35 PM
Plato
Re: Boolean Algebra Help
Quote:

Originally Posted by normanthefish
I need help with simplification.
x = nA.nB.C + nA.B.nC + nA.B.C + A.nB.nC
Wasn't sure how to show a NOT so used a small (n) in front of the letter to display that it was notted. If you could give me any tips to solve this or help that would be much appreciated.

$$x = \neg A\cdot \neg B\cdot C + \neg A\cdot B\cdot \neg C + \neg A\cdot B\cdot C + A\cdot \neg B\cdot \neg C$$ gives $x = \neg A\cdot \neg B\cdot C + \neg A\cdot B\cdot \neg C + \neg A\cdot B\cdot C + A\cdot \neg B\cdot \neg C$
Click on the “go advanced” tab. On the toolbar you will see $\boxed{\Sigma}$ clicking on that give the LaTeX wraps, . The code goes between them.
• November 22nd 2012, 02:37 PM
emakarov
Re: Boolean Algebra Help
The only simplification seems to be factoring out (~A)B from the second and third term (and replacing C + ~C with T).
• November 22nd 2012, 02:58 PM
normanthefish
Re: Boolean Algebra Help
Still confused with the symbols to use so sticking with what i know.

managed to get x = nA.nB.C + nA.B + A.nB.nC

if that is what you meant
• November 22nd 2012, 03:22 PM
emakarov
Re: Boolean Algebra Help
Yes, this was my idea.