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Math Help - Combination

  1. #1
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    Combination

    I am not sure if I am doing the following problem correctly.
    A six person person committee composed of A, B, C, D, E, F, is to select a chairperson, a secretary, and a treasurer. How many selections include A or B or both?

    Ways for A and not B: 1 (position 1 i.e, A) * 4 (position 2) * 3 (position 3) * 3! (ways to arrange the selections in the 3 positions) = 72
    Ways for B and not A: 1*4*3*3! = 72
    Ways for B and A: 1*1*4*3! = 24

    72 + 72 + 24 = 168
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  2. #2
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    NY
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    Re: Combination

    I had another thought on how to solve this problem.
    nPr(6,3) (the total possible ways to select the positions) - nPr(4,3) (the ways to select the positions without a or b) = 96
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