# Thread: Quicky Question involving sets

1. ## Quicky Question involving sets

{a,b,c{a,b}} \ P(A)

is the {a} in the power set = to the a in the left side of the equation, or should {a} and a be considered completely different objects?

Thanks

2. Originally Posted by Eclyps19
{a,b,c{a,b}} \ P(A) is the {a} in the power set = to the a in the left side of the equation, or should {a} and a be considered completely different objects?
As written the question is almost unreadable!
First, should it be {a,b,c,{a,b}}?
Next, what is the set A? Without knowing that, P(A) is meaningless!
Please correct the posting!

3. sorry, I'm sitting in class right now and my math teacher really doesn't know his stuff.

Say I have {a,b,c,{a,b}} \ P(a,b,c,{a,b}}. When pulling out the elements for the power set, I will eventually come to a {a}. Does this {a} = a from the original? I'm debating my teacher saying that these should be equal, since you're basically saying the element of a is = to the element of a. He keeps bringing up empty set is not equal to {empty set}.

Is this any better? Sorry

4. {a,b,c,{a,b}} \ P(a,b,c,{a,b}}={a,b,c}
The only subset of {a,b,c,{a,b}} to be removed is the subset {a,b}.

5. alright that's all I needed. Thank you very much