Define a sequence a0 a1 a2. . . recursively by setting a0 = 1 and an+1= 3 – 1/an for all n= 0, 1, 2, 3, . . . use induction to prove that 0 < an < an + 1 < 3 for all n = 0, 1, 2, 3, . . .
Define a sequence a0 a1 a2. . . recursively by setting a0 = 1 and an+1= 3 – 1/an for all n= 0, 1, 2, 3, . . . use induction to prove that 0 < an < an + 1 < 3 for all n = 0, 1, 2, 3, . . .
hey thanks alot. but i am still having a bit of difficulties with the -a^2(subscript n). i understand that the [3a(subscript n) -1]/a(subscript n) came from the a(subscript n+1) but i don't understand how -a(subscript n) gives u that -a^2(subscript n)