I'm solving an assignment for class tomorrow and have to verify that this relation is a function.
The relation f in real is given by
xfy <=> (y(2x-3)-3x=y(x^2-2x)-5x^2)
Function: A function is a set of ordered pairs in which each x-element has only ONE y-element associated with it.
I decided to isolate y in the relation:
Divides with y on both sides:
4x-3-3x/y=x^2-(5x^2)/y <=>4x-3-x^2=3x/y - (5x^2)/y
When i do a graph for y. I see that the relation isnt a function, since the relation shares coordinates on x about =[0;2] (*the exact value doesnt matter)