Suppose that A is contained in the set of all real numbers and is bounded above. Prove that if A contains one of its upper bounds, then this upper bound is sup A.

It seems like it should be a simple problem, but I'm lost.

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- September 23rd 2012, 08:51 AMlovesmathUpper Bounds and Supremums
Suppose that A is contained in the set of all real numbers and is bounded above. Prove that if A contains one of its upper bounds, then this upper bound is sup A.

It seems like it should be a simple problem, but I'm lost. - September 23rd 2012, 09:34 AMPlatoRe: Upper Bounds and Supremums