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Math Help - How to prove that X={(x1, x2) | x2-3 >= -x1^2, x1, x2 >= 0} is a convex set?

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    How to prove that X={(x1, x2) | x2-3 >= -x1^2, x1, x2 >= 0} is a convex set?

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    Re: How to prove that X={(x1, x2) | x2-3 >= -x1^2, x1, x2 >= 0} is a convex set?

    A set C in S is said to be convex if, for all x and y in C and all t in the interval [0,1], the point  (1-t ) x + t y is in C. Convex set - Wikipedia, the free encyclopedia


    Are you sure it is  X=\{(x_1, x_2) | x_2 - 3 \ge -x_1^2, x_1, x_2 \ge 0\} and not  X=\{(x_1, x_2) | x_2 - 3 \le -x_1^2, x_1, x_2 \ge 0\}
    Last edited by kalyanram; September 12th 2012 at 09:53 AM.
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