Cross Products and Set Unions Proof
I'm hoping this is the right category, since it's set theory. If it's not I'll move it if someone knows a better place for these questions
Prove that A X (B1U B2) = (A X B1) U (A X B2)
I am actually stuck on the B1 B2 in this problem. It's some notation aspect that is keeping me from understanding what the problem is asking for. Are B1 and B2 separate sets?
Re: Cross Products and Set Unions Proof
Quote:
Originally Posted by
renolovexoxo 
Are B1 and B2 separate sets?
Yes, B1 and B2 are arbitrary sets. The problem is asking to prove that A x (B U C) = (A x B) U (A x C) for arbitrary sets A, B, C.
Re: Cross Products and Set Unions Proof
Quote:
Originally Posted by
renolovexoxo I'm hoping this is the right category, since it's set theory. If it's not I'll move it if someone knows a better place for these questions
Prove that A X (B1U B2) = (A X B1) U (A X B2)
![\begin{align*}(x,y)\in A\times (B\cup C)&\text{if and only if }x\in A\text{ and }y\in (B\cup C) \\&\text{if and only if }x\in A\text{ and }(y\in B\text{ or }y\in C) \\&\text{if and only if }[x\in A\text{ and }(y\in B)]\text{ or }[ x\in A\text{ and }(y\in C))] \\&\text{if and only if }(x,y)\in(A\times B)\text{ or }(x,y)\in(A\times C)\end{align*}](http://latex.codecogs.com/png.latex? \begin{align*}(x,y)\in A\times (B\cup C)&\text{if and only if }x\in A\text{ and }y\in (B\cup C) \\&\text{if and only if }x\in A\text{ and }(y\in B\text{ or }y\in C) \\&\text{if and only if }[x\in A\text{ and }(y\in B)]\text{ or }[ x\in A\text{ and }(y\in C))] \\&\text{if and only if }(x,y)\in(A\times B)\text{ or }(x,y)\in(A\times C)\end{align*})
