# Proove this theorem via contradiction

• August 2nd 2012, 12:18 PM
omegatidus
if x+y>100 then x>50 or y>50
• August 2nd 2012, 12:23 PM
Plato
Re: Proove this theorem via contradiction
Quote:

Originally Posted by omegatidus
if x+y>100 then x>50 or y>50

Suppose that $x\le50~\&~y\le 50$ then $x+y\le~?$
• August 2nd 2012, 12:23 PM
GJA
Re: Proove this theorem via contradiction
Start by assuming the negation of "x>50 or y>50." Then see if what you get somehow contradicts "x+y>100."

If this is too cryptic let me know and I will be a bit more explicit. Good luck!