Proove this theorem via contradiction

if x+y>100 then x>50 or y>50

Quote:

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Originally Posted by omegatidus

if x+y>100 then x>50 or y>50

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Suppose that then

Start by assuming the negation of "x>50 or y>50." Then see if what you get somehow contradicts "x+y>100."

If this is too cryptic let me know and I will be a bit more explicit. Good luck!