I think you're a little confused.
Squares of even numbers are even so 4k+3, which is odd of course, is not the square of an even number.
Squares of odd numbers are of the form (2m+1)^2 = 4m^2+4m+1 = 4(m^2+m) + 1 which is of the form 4k+1.
Im stuck on this homework problem that im not sure if i am doing right and it is due tommorow:
Prove that there is no perfect square of the form 4k+3?
Case 0:
k is even
k=2n for some n in Z
4(2n)+3=8n+3 which is odd so there is no perfect square if k is even
Case 1:
k is odd
k=2n+1 for some n in Z
4(2n+1)+3 = 8n+7 which is not of the form 4k+3 there for there is no perfect square
I think you're a little confused.
Squares of even numbers are even so 4k+3, which is odd of course, is not the square of an even number.
Squares of odd numbers are of the form (2m+1)^2 = 4m^2+4m+1 = 4(m^2+m) + 1 which is of the form 4k+1.
Note: this solution's similar to a tutor's solution, but uses mods instead. Note that n must be odd. We have two cases:
. Then
. Then .
In either of these cases , that is, it cannot be written in the form 4k+3, k integer. Hence we're done.