# Thread: Simplify formula for rate of change of Volume

1. ## Simplify formula for rate of change of Volume

I need to simplify further the formula for the volume of a cylinder in pdf attached. I also need to interpret it.
Can you give me some hints? thanks

2. ## Re: Simplify formula for rate of change of Volume

Your PDF does not make much sense. I suggest you post the WHOLE question with ALL relevant information, not just the bits you think are appropriate.

3. ## Re: Simplify formula for rate of change of Volume

You are given that the volume of cylinder of radius r and height h is $\displaystyle \pi r^2h$, that $\displaystyle h= \frac{10}{\pi r^2}$ and that $\displaystyle r= 3+ 2sin(t)$.

ONE way to do this is to replace h in the volume formula with that formula in terms of r:
$\displaystyle V= \pi r^2h= \pi r^2\frac{10}{\pi r^2}= 10$ and then replace "r" in that by its formula in terms of t.

Oh, wait- there is no "r" in that formula- the "$\displaystyle \pi r^2$" terms canceled out and we got V= 10, a constant! Well, what does that tell you about its derivative?

4. ## Re: Simplify formula for rate of change of Volume

Originally Posted by HallsofIvy
You are given that the volume of cylinder of radius r and height h is $\displaystyle \pi r^2h$, that $\displaystyle h= \frac{10}{\pi r^2}$ and that $\displaystyle r= 3+ 2sin(t)$.

ONE way to do this is to replace h in the volume formula with that formula in terms of r:
$\displaystyle V= \pi r^2h= \pi r^2\frac{10}{\pi r^2}= 10$ and then replace "r" in that by its formula in terms of t.

Oh, wait- there is no "r" in that formula- the "$\displaystyle \pi r^2$" terms canceled out and we got V= 10, a constant! Well, what does that tell you about its derivative?
This is exactly why I have a feeling that the OP did not post all the information. E.g. looking at the given \displaystyle \displaystyle \begin{align*} h = \frac{10}{\pi r^2} \end{align*}, that implies straight away that the volume is always \displaystyle \displaystyle \begin{align*} 10 \end{align*}, where in the given context it might only start out being \displaystyle \displaystyle \begin{align*} 10 \end{align*}...