I have no idea how to solve this. Any help would be appreciated! The statement is

For any setsA, B,andCthat are subsets of a universal setU, A-(B∩C)=(A-B)∪(A-C).

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- April 25th 2012, 04:05 PMgoalkeeper00Math Proof A-(B∩C)=(A-B)∪(A-C).
I have no idea how to solve this. Any help would be appreciated! The statement is

For any sets*A, B,*and*C*that are subsets of a universal set*U*, A-(B∩C)=(A-B)∪(A-C). - April 25th 2012, 04:11 PMigniteRe: Math Proof A-(B∩C)=(A-B)∪(A-C).
Use following properties:

X-Y=X∩Y'

(X∩Y)'=X'∪Y'

A-(B∩C)=A∩(B∩C)'=A∩(B'∪C')=(A∩B')∪(A∩C')=(A-B)∪(A-C) - April 25th 2012, 04:17 PMPlatoRe: Math Proof A-(B∩C)=(A-B)∪(A-C).
- April 27th 2012, 08:46 AMHallsofIvyRe: Math Proof A-(B∩C)=(A-B)∪(A-C).
Or use the basic definitions: if x is in then x is in A but not in . That, in turn, means it is either NOT in B or NOT in C.

case 1: x is in A but not in B. Then it is in .

case 2: x is in A but not in C. Then it is in .