It is very hard to follow what you have written.
However, here are some standard equivalencies.
Hi,
I have to express "p | q" (p or q) by using only =>~ (implies not)
I posted this yesterday night, this morning I looked at it again and I came up with a solution:
Let ->~ be *
p|q is equivalent to (( ((P*Q)*P) * ( (P*Q)*Q))*(P*Q) ) * (((p*q)*(p*q))*q)
My first approach was using truth tables, finding new ones and trying to combine them to get the result I am looking for. This worked in the end, I was able to find a working combination with those truth tables I created, but there must be better ways to solve this kind of problems and to make sure one gets as simple a solution as possible, mine seems too long to be the simplest one.
Anyone knows the right way to solve this?
Thank you