Re: How would you prove...
Quote:
Originally Posted by
Cairo
How would you prove that
(A/B) U B = A if and only if B C A ?
There is no one way to do any set theory proof.
Here you might note that  \equiv \left( {A \cap B^c } \right))
Starting with
what would \cup A=~?)
Re: How would you prove...
Quote:
Originally Posted by
Cairo
How would you prove that
(A/B) U B = A if and only if B C A ?
It's the iff that is giving me problems. Is there a technique for this type of proof?
This statement is equivalent to the following statement :
iff 
Re: How would you prove...
Quote:
Originally Posted by
princeps
This statement is equivalent to the following statement :
 \lor q \Leftrightarrow p)
iff

Thanks, but this looks even worse to me!
Re: How would you prove...
Would this not be A, Plato?
I was thinking of relabelling (B C A) as D and ((A/B) U B = A) as E and then trying to argue D implies E and also that ~D implies ~E, but not sure if this would work or even where to start.
Re: How would you prove...
Quote:
Originally Posted by
Cairo
Would this not be A, Plato?
That is correct. So you have proved it one way.
Now suppose that
now show that 
Re: How would you prove...
Quote:
Originally Posted by
Plato
That is correct. So you have proved it one way.
Now suppose that
\cup B=A)
now show that

Using the distributive law I get
(A U B) and (B^c U B) = .......
But not sure how to continue this argument.
Will have a think about it.
Re: How would you prove...
Quote:
Originally Posted by
Plato
There is no one way to do any set theory proof.
Here you might note that
Starting with

what would
\cup A=~?)
Should not
be \cup B)
And then be equal to:
?