$\displaystyle \sum_{i = 1}^n i^3 = \frac{n^2(n+ 1)^2}{4}$?

Printable View

- Sep 24th 2007, 02:34 PMEdbaseball17Prove By Induction (Sigma Style)
$\displaystyle \sum_{i = 1}^n i^3 = \frac{n^2(n+ 1)^2}{4}$?

- Sep 24th 2007, 03:53 PMPlato
This is such a standard problem; you will find it worked on the web.

Have you done a web search?

It is pointless to recreate the wheel. - Sep 24th 2007, 04:42 PMWWTL@WHL
Can you show your working so far? :)