How many EVEN 7 digit inters there using only the digits 2,3,4,5,6,7,8? EDIT: forgot to add the word even.
I thought this was easy, but when I got my assignment back it was wrong.
For my answer I put 4*6!
4 ways to put either 2,4,6,8 in the last position multiplied by 6! as the ways we can arrange the rest of the numbers.
If this is incorrect.....what am i missing?
edit: I also got zero on a similar question.
In a class of 19 children, with 11 boys and 8 girls - how many ways can we choose a team of 10 children containing at least 5 boys?
(11c5) to select the boys. Multiplied by (14c5) to select the rest of the 5 students.
The correct solution apparently is (11c5)(8c5)+(11c6)(8c4)+(11c7)(8c3)+(11c8)(8c2)+(1 1c9)(8c1)+(11c10)(8c0)