I sorta know how to transform this sum, but only by heart.
I'd really like to understand why it transforms like it does. Can anyone explain it to me..?
If You denote with the Z-transform of , the Z-transform of and the Z-transform of , then You have the well known relation...
If You have , that means that is and is...
... so that (2) becomes...
Marry Christmas from Serbia
I just realised, it's convolution, right?
I've seen differential equations described with series. Can the transform of for instance in a series can be written like this?
If we have .
Is this the way of setting up a solution using z-transform to for instance: