Find the number of different arrangements of the letters in the word
COONABARABRAN
How many of those arrangements (i) start with the six vowels; (ii) contain the
four letters ‘A’ consecutively; (iii) contain no two consecutive letters ‘A’?
Answer:
Total number of arrangements: = 16216200
(i) Put As and Os at start = 15. Then number of arrangements of NNRRBBC is = 630. 15 * 630 = 9450
(ii) Treat AAAA as one item. That means there are 10 items to arrange - AAAA C O O N N B B R R. = 18900 ways.
(iii) _C_O_O_N_N_B_B_R_R_ ---> Put As in the gaps. This can be done = 210 ways. Number of arrangements of COONNBBRR = = 22680. 210 * 22680 = 4762800.
Are those answers correct?