Hi

I am trying to prove that if $\displaystyle A\sim B$ then

$\displaystyle \mathcal{P}(A)\sim \mathcal{P}(B)$

Now $\displaystyle A\sim B$ means that there is some bijection from A to B. And I need

to prove that there is also some bijection from $\displaystyle \mathcal{P}(A)$ to

$\displaystyle \mathcal{P}(B)$. So first thing, I need to come up with some function and then prove that its one to one and onto.

Can people provide me some hints to begin with to come up with such a function ?

Thanks