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About LinkBacksFindwith respect to U=R in the following case.
The answer isHow do you know if it's an open interval or a closed interval?
Since open sets do not contain their boundary, their compliment must contain all points that are in the boundary of the original set (where open) and not contain the boundary when it's there (when closed).
Think of the interval as a set of points. Note that -2 is in A and 1 is not in A. This means
Your answer is not correct. The answer is. -2 can't be in
. 1 must be in
You were told that you were only dealing with real numbers, andOriginally Posted by Jskid
Yes that is clear, just one point is not. Why must it be an open interval for?
and
are not real numbers. Therefore they are neither in A, nor its compliment.
They mean that infinity always appears as an open interval, I presume. Unless you're using the extended real line (which adds one extra point for each ofWhat does "to be an open interval for" mean? I also assume you mean. Finally, this question is not related to the problem in the OP, is it?
and
), those values are not real numbers and as such they cannot be in the compliment.
Another way of saying that: the real line has no greatest or least element. It cannot be both closed and unbounded at the same time in the same direction, so "infinity" will never appear as the closed endpoint of an interval on the real numbers.
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