I broke them up into 2 cases:
Case 1: Belle and Candy sits at 6 seater = 8C4 x 4! x 4C4 x 3!
Case 2: Belle and Candy sits at 4 seater = 8C2 x 2! x 6C6 x 5!
Adding them up gives 16800 but answer is 33600 (2times my answer)
Belle and Candy went out with 8 other friends to have lunch at a restaurant. They were shown to 2 round tables: one a 4-seater, and the other a 6-seater.
Find the no. of ways the members of this group could be seated if Belle and Candy wish to sit next to each other.
I broke them up into 2 cases:
Case 1: Belle and Candy sits at 6 seater = 8C4 x 4! x 4C4 x 3!
Case 2: Belle and Candy sits at 4 seater = 8C2 x 2! x 6C6 x 5!
Adding them up gives 16800 but answer is 33600 (2times my answer)