I am doing the following question.

"5. How many poker hands are there that contain at least one of 10@, QB, AC, or 6D ?

Show your work."

For my solution I did

A=52*(51C4)

B=52*51*(50C3)

C=52*51*50*(49C2)

D=52*51*50*49*(48C1)

then

A+B+C+D=E

Does this seem to make sense?